Differentiation A-Level Maths: Every Rule, Every Exam Application
From the chain rule to implicit differentiation to connected rates of change — the complete A-Level Maths differentiation guide with every technique examiners test.
Why differentiation runs through every A-Level paper
Differentiation isn't just a topic — it's a tool. It appears directly in calculus questions but also implicitly in curve sketching, optimisation, mechanics (velocity and acceleration), and rates of change problems.
A student who can differentiate fluently and accurately can access marks across the entire paper. A student who can't will find large sections of every paper inaccessible.
The core differentiation rules (and when to use each)
Power rule
d/dx(xⁿ) = nxⁿ⁻¹
This works for any constant power — positive, negative, or fractional. Before differentiating, simplify: write √x as x^(1/2), write 1/x² as x⁻².
Chain rule
d/dx(f(g(x))) = f'(g(x)) · g'(x)
Use whenever you have a function of a function: (2x+1)⁵, sin(x²), eˣ³, ln(3x−1). Identify the outer function and inner function. Differentiate the outer (keeping the inner), then multiply by the derivative of the inner.
Product rule
d/dx(uv) = u·dv/dx + v·du/dx
Use whenever two functions are multiplied together: x²sin x, xeˣ, x³ln x.
Memory aid: "first times derivative of second, plus second times derivative of first."
Quotient rule
d/dx(u/v) = (v·du/dx − u·dv/dx) / v²
Use for fractions where both numerator and denominator are functions of x. Note: the minus sign in the numerator means order matters. Numerator is always (bottom × derivative of top) − (top × derivative of bottom).
Implicit differentiation
For equations involving both x and y where you can't easily rearrange for y:
- Differentiate every term with respect to x
- Every time you differentiate a term containing y, multiply by dy/dx (chain rule)
- Collect dy/dx terms and solve
Example: x² + y² = 25
Differentiating: 2x + 2y(dy/dx) = 0
Solving: dy/dx = −x/y
The most tested applications
Finding stationary points
- 1Differentiate to get dy/dx
- 2Set dy/dx = 0 and solve for x
- 3Find y by substituting into original equation
- 4Determine nature using second derivative: if d²y/dx² > 0, minimum; if < 0, maximum; if = 0, further investigation needed
Optimisation problems
These questions give you a constraint and ask you to minimise or maximise something.
- 1Express the quantity to minimise/maximise as a function of one variable (use the constraint to eliminate others)
- 2Differentiate and set to zero
- 3Verify it's a minimum or maximum using the second derivative
- 4Check boundary conditions if the domain is restricted
Connected rates of change
Using the chain rule across rates: if you know dV/dt and want dr/dt, and you know V in terms of r:
dV/dt = dV/dr × dr/dt
These questions always give you the related quantities — your job is to connect them through the chain rule.
Parametric differentiation
When x = f(t) and y = g(t):
dy/dx = (dy/dt) ÷ (dx/dt)
For the second derivative: d²y/dx² = (d/dt(dy/dx)) ÷ (dx/dt)
The errors that cost A-level students marks
- 1Forgetting to apply the chain rule — d/dx(sin(2x)) = cos(2x), not cos(2x). The inner derivative (2) must multiply.
- 1Product rule sign errors — Always write u, v, du/dx, dv/dx separately before applying the formula
- 1Implicit differentiation — forgetting the dy/dx when differentiating terms containing y: d/dx(y²) = 2y(dy/dx), not just 2y
- 1Not checking stationary point nature — A question asking for a maximum or minimum requires confirmation via second derivative or sign change. A stationary point isn't automatically a maximum or minimum.
- 1Rates of change sign — If a quantity is decreasing, its rate of change is negative. Don't lose the sign.
How to build differentiation fluency
Generate 20 differentiation questions in Infinity Stars mixing: basic power rule, chain rule, product rule, implicit, and connected rates. Don't label what technique you need — that's the examiner's job, not yours.
In the real exam, the technique isn't named. "Find dy/dx" for x²sin x is a product rule question. "Find the gradient of the curve x² + 3xy + y² = 7 at the point (1,1)" is implicit differentiation. You need to identify and execute without prompting.
That identification skill only develops through unseen practice.
Practice makes A*
Generate unlimited questions on any chapter from this article — with full worked solutions.
Start Free Trial — £5